Respuesta :
Using the rule for 2x2 matrices,
[tex]\begin{vmatrix}a&b\\c&d\end{vmatrix}=ad-bc[/tex]
the determinant for your matrix is
[tex]\begin{vmatrix}5&-4\\8&2\end{vmatrix}=5\times2-(-4)\times8=42[/tex]
[tex]\begin{vmatrix}a&b\\c&d\end{vmatrix}=ad-bc[/tex]
the determinant for your matrix is
[tex]\begin{vmatrix}5&-4\\8&2\end{vmatrix}=5\times2-(-4)\times8=42[/tex]
Answer:
Option C, 42
Step-by-step explanation:
As you have mentioned the matrix in the comment section. We have to find the determinant.
A = [tex]\begin{bmatrix}5 & -4\\ 8 & 2\end{bmatrix}[/tex]
Now determinant of this matrix will be written as
|A| = 5 × 2 - 8 ( -4 )
= 10 + 32
= 42
Option C is the answer.