[tex]\textit{Actor A charges 250 plus 50 per day}
\\ \quad \\
\begin{array}{llll}
days&charge
\\---&---\\
1&50\cdot 1\\
2&50\cdot 2\\
3&50\cdot 3\\
4&50\cdot 4\\
d&50\cdot x\implies 50d
\end{array}\quad meaning\implies A=250+50d[/tex]
[tex]\textit{Actor B charges 2500 plus 60 per day}
\\ \quad \\
\begin{array}{llll}
days&charge
\\---&---\\
1&60\cdot 1\\
2&60\cdot 2\\
3&60\cdot 3\\
4&60\cdot 4\\
d&60\cdot x\implies 60d
\end{array}\quad meaning\implies B=200+60d
\\ \quad \\
when\ is A=B?\qquad well
\\ \quad \\
250+50d\quad =\quad 200+60d\impliedby \textit{solve for days "d"}[/tex]