Respuesta :
The kinetic energy of the ball is
KE = 1/2 (0.25) (14)²
KE = 24.5 J
Equate it to the potential energy of the ball when it's dropped which is
PE = 0.25 (9.81) h
PE = 2.45 h
Equating...
24.5 = 2.45 h
Solve for h
h = 10 m
The bottle was dropped 10 m above the ground.
KE = 1/2 (0.25) (14)²
KE = 24.5 J
Equate it to the potential energy of the ball when it's dropped which is
PE = 0.25 (9.81) h
PE = 2.45 h
Equating...
24.5 = 2.45 h
Solve for h
h = 10 m
The bottle was dropped 10 m above the ground.