Guys please helpppp!!!!


An equilateral triangle (all 3 sides are the same length) sits on top of a square. They both share the side AB

Guys please helpppp An equilateral triangle all 3 sides are the same length sits on top of a square They both share the side AB class=

Respuesta :

Answer:

6x +15

Step-by-step explanation:

To solve for the perimeter of the triangle, we need to find the length of each side.

(a +b)² = a² +2ab +b²

Let's factorise the expression for the area of the square:

Area of square

= 4x² +20x +25

= (2x +5)²

Since area of square= side ×side, length of a side of the square is the square root of its area. We are also given that the side of the square is AB.

(AB)²= (2x +5)²

Taking the square root of both sides:

AB= 2x +5

The perimeter is the sum of the lengths of all of its sides.

Perimeter of the triangle

= 3(AB)

= 3(2x +5)

= 6x +15