Respuesta :

Lets see

  • Interest=I=3600
  • Rate of interest=R=3%
  • Time=T=3yrs

  • Principle=P

[tex]\\ \rm\longmapsto I=\dfrac{PRT}{100}[/tex]

[tex]\\ \rm\longmapsto P=\dfrac{100I}{RT}[/tex]

[tex]\\ \rm\longmapsto P=\dfrac{360000}{9}[/tex]

[tex]\\ \rm\longmapsto P=Rs.40000[/tex]

Solution:

We know that:

  • Interest = ₹ 3,600
  • Time = 3 years
  • Rate = 3%

Let "P" represent the money Anita borrowed.

[tex]\dfrac{\text{P} \times 3 \times 3}{100} = 3,600[/tex]

[tex]\rightarrow \dfrac{\text{P} \times 9}{100} = 3,600[/tex]

[tex]\rightarrow \dfrac{\text{P} }{100} = 400[/tex]

[tex]\rightarrow \ \text{P }= \text{R.S} \ 40000[/tex]

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