bigbrain69
contestada

Nitrogen gas and hydrogen gas react to produce ammonia according to the following equation.


N2 + 3H2 → 2NH3


The atomic mass of nitrogen is 14 g/mol. The atomic mass of hydrogen is 1 g/mol. When the reaction produces 68 grams of ammonia, how many grams of nitrogen were present initially?


A 4

B 56 ***

C 12

D 112

Respuesta :

bilaal6090

Specific Mass Conversions Quick Check:

  1. It compares the mass of the products to the mass of the reactants.
  2. For every 3 moles of hydrogen gas, the reaction produces 2 moles of ammonia.
  3. 56
  4. 32 g/mol
  5. 4
ajinems

The amount of nitrogen that would produce 68grams of ammonia = 56 g/mol

Calculation of amount of nitrogen

The atomic mass of nitrogen is = 14 g/mol

2 atoms of nitrogen = 2 × 14 = 28 g/mol

The molecular mass of ammonia produced from 28 g/mol of nitrogen = 2(14+ 3)

= 2 × 17

= 34g/ mol

if 28g of Nitrogen = 34g/mol of ammonia

xg of Nitrogen = 68g/mol of ammonia

Make X the subject of formula,

X ,= 28 × 68/34

X = 1904/34

X = 56 g/mol of Nitrogen

Therefore, 56 g/mol of Nitrogen were present initially.

Learn more about atomic mass here:

https://brainly.com/question/3187640

Otras preguntas