A rectangle with constant area has possible lengths and widths as shown in the table below. width vs. length of a rectangle width (w) length (l) 2 37.5 4 18.75 6 12.5 8 9.375 which equation can be used to find any corresponding length and width that fit the pattern in this table? l = startfraction k over w endfraction, where l is the length, w is the width, and k is a constant (w not-equals 0) l = m w b, where l is the length, w is the width, and m and b are constants l = k w superscript one-half, where l is the length, w is the width, and k is a constant l = a w squared, where l is the length, w is the width, and a is a constant

Respuesta :

The equation, which is used to find any corresponding length and width that fit the pattern in the provided table is,

[tex]I=\dfrac{k}{w}[/tex]

What is the area of a rectangle?

Area of a rectangle is the product of the length of the rectangle and the width of the rectangle. It can be given as,

[tex]A=a\times b[/tex]

Here, (a)is the length of rectangle and (b) is the width of the rectangle.

A rectangle with constant area has possible lengths and widths as shown in the table below.

Width vs. Length of a rectangle

  • width (w)       2       4        6        8
  • length (l)     37.5  18.75  12.5   9.375  

In the above table, the length of a rectangle is decreasing with increasing the width of a rectangle.

For such relation, the value of w should be inversely proportional to the length of it. The first option given as,

[tex]I=\dfrac{k}{w}[/tex]

Here l is the length, w is the width, and k is a constant (w not-equals 0).

In this expression, the length of the rectangle is inversely proportional to the width of the rectangle.

Thus, the equation, which is used to find any corresponding length and width that fit the pattern in the provided table is,

[tex]I=\dfrac{k}{w}[/tex]

Learn more about the area of rectangle here;

https://brainly.com/question/11202023

Answer:

a

Step-by-step explanation: