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A student decided to use the titration technique to find out the concentration of
Acetylsalicylic acid (ASA) from a sample that arrived at the laboratory. He
took three samples of 0.1830, 0.1903 and 0.1851 (grams) and titrated with NaOH
0.497 M and spent on the titration 16.0 – 18.3 and 17.3 ml respectively in each
sample. Calculate the percentage of acetylsalicylic acid in the samples. THE
Sample packaging says contain 92% AAS, calculate absolute and relative error
in this degree.
C8H7O2COOH(aq) + NaOH(aq) C8H7O2COONa(aq) + H2O(l)

Respuesta :

mickymike92

From the mole ratio of the reaction, the mass of ASA reacted is greater than the mass of ASA sample indicating an error in some of the data provided.

What is the titration technique?

Titration is a technique in analytical chemistry in which the volume of solution A of known concentration needed to react with another solution B of unknown concentration is used to determine the unknown concentration of the solution B.

The equation of the reaction between acetylsalicylic acid (ASA) and NaOH is given below:

  • C8H7O2COOH(aq) + NaOH(aq) C8H7O2COONa(aq) + H2O(l)

1 mole of ASA reacts with one mole of NaOH

Molar mass of ASA = 180 g/mol

For first sample:

Volume of NaOH = 16.0 mL = 0.016 L

Moles of NaOH reacted = 0.016 × 0.497 = 0.007952 moles

Therefore, moles of ASA reacted = 0.007952 moles

Mass of ASA reacted = 1.43136 g

However, mass of ASA sample = 0.1830 g

The mass of ASA reacted is greater than the mass of ASA sample.

This means there is an error in the data provided.

Learn more about titration at: https://brainly.com/question/13307013

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