contestada

The chemical equation below shows the decomposition of nitrogen triiodide (ni3) into nitrogen (n2) and iodine (i2). 2ni3 right arrow. n2 3i2 the molar mass of ni3 is 394.71 g/mol. how many moles of i2 will form 3.58 g of ni3? 0.00907 moles 0.00940 moles 0.0136 moles 0.0212 moles

Respuesta :

The moles of diiodine is formed from the nitrogen triiodide is 0.0212 moles.

How we calculate moles from mass?

Relation between the moles and mass of any substance will be represented as:

n = W/M, where

n = moles

W = given mass

M = molar mass

Given chemical reaction is:

2NI₃ → N₂ + 3I₂

Moles of 5.58g of NI₃ will be calculated as:
n = 5.58g / 394.71g/mol = 0.0141 mole

From the stoichiometry of the reaction, it is clear that:
2 moles of NI₃ = produce 3 moles of I₂

0.0141 moles of NI₃ = produce 3/2×0.0141=0.02115 = 0.0212 moles of I₂

Hence option (4) is correct i.e. 0.0212 moles.

To know more about moles, visit the below link:
https://brainly.com/question/25680776

Otras preguntas