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You have a cup with 16 coins inside. The total inside the cup is $2.20. Determine how many quarters and nickels are inside the cup. Use a system of equations. Be sure to define the variables and show all work.

Respuesta :

Answer:

7 quarters

9 nickels

Step-by-step explanation:

Let q = number of quarters

Let n = number of nickels

Nickel = $0.05

Quarter = $0.25

Given:  total of coins in the cup = 16

⇒ n + q = 16

Given:  total inside the cup = $2.20

⇒ 0.05n + 0.25q = 2.20

Rewrite  n + q = 16  to make n the subject:

⇒ n = 16 - q

Substitute  n = 16 - q  into  0.05n + 0.25q = 2.20  and solve for q:

⇒ 0.05(16 - q) + 0.25q = 2.20

⇒ 0.8 + 0.2q = 2.20

⇒ 0.2q = 1.4

⇒ q = 7

Now substitute found value for q into  n = 16 - q  and solve for n:

⇒ n = 16 - 7

⇒ n = 9

Therefore, there are 7 quarters and 9 nickels in the cup.

Answer: 9 nickels and 7 quarters

Step-by-step explanation:

Let N be the number of nickels in the cup

Let Q be the number of quarters in the cup

For the first equation, we will be using the total number of coins in the cup .

N + Q = 16

Q = 16 - N...Equation 1

We know that a nickel = 5 cents and a quarter is 25 cents. Now, substitute the number of nickels in in dollars

0.05 N + 0.25Q = 2.20...Equation 2

Use substitution to solve for two equations to solve for the problem:

[tex]\begin{aligned}0.05 N+0.25 Q &=2.20 \\0.05 N+(16-N)(0.25)=2.20 \\0.05 N+4-0.25 N=2.20 \\0.05 N-0.25 N &=2.20-4 \\-0.2 N &=-1.8 \\N &=9 \\\end{aligned}[/tex]

Now, substitute the number of nickels in in dollars in Equation 1 to get the number of quarters.

N + Q = 16

9 + Q = 14

Q = 16- 9

Q = 7

Therefore, there are 9 nickels and 7 quarters in the cup