The final speed of the second puck is 5 m/s.
What is speed?
Speed can be defined as the rate of change of distance with respect to time.
To calculate the final speed of the second puck, we use the formula below.
Formula:
- mu+m'u' = mv+m'v'................ Equation 1
Where:
- m = mass of the first puck
- m' = mass of the second puck
- u = initial velocity of the first puck
- u = initial velocity of the second puck
- v = final velocity of the first puck
- v' = final velocity of the second puck.
Make v' the subject of the equation
- v' = (mu+m'u'-mv)/m'.............. Equation 2
Assuming,
- The mass of the first puck is y
- The left direction is negative and the right direction is positive
From the question,
Given:
- m = y
- m' = 2y
- u = 5 m/s
- u' = -2 m/s
- v = -9 m/s ( rebounds)
Substitute these values into equation 2
- v' = [(y×5)+(2y×(-2))-(y×(-9))]/2y
- v' = (5y-4y+9y)/2y
- v' = 10y/2y
- v' = 5 m/s
Hence, The final speed of the second puck is 5 m/s.
Learn more about speed here: https://brainly.com/question/6504879
