The chemical equation below shows the combustion of propane (c3h8). c3h8 5o2 right arrow. 3co2 4h2o the molar mass of oxygen gas (o2) is 32.00 g/mol. the molar mass of c3h8 is 44.1 g/mol. what mass of o2, in grams, is required to completely react with 0.025 g c3h8? 0.018 grams 0.034 grams 0.045 grams 0.091 grams

Respuesta :

The mass of oxygen required to completely react with C₃H₈ is 0.091 grams.

How we calculate moles from mass?

Moles of any substance will be calculated as:

n = W/M, where

W = given mass

M = molar mass

Given chemical reaction is:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Moles of 0.025g of C₃H₈ will be calculated as:

n = 0.025g / 44.1 g/mol = 0.00056 moles

From the stoichiometry of the reaction it is clear that:

1 mole of C₃H₈ = react with 5 moles of O₂

0.00056 mole of C₃H₈ = react with 5×0.00056=0.0028 moles of O₂

Now we calculate the mass of oxygen by using the above moles and molar mass as:

W = (0.0028mol)(32.00 g/mol) = 0.0896g = 0.090g

Which is approx to the given valoe 0.091g.

Hence correct option is (d).

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