1) The reflected function [tex]g(x)=-2(3.5)^x[/tex] is defined everywhere.
2) Initial value of g(x) or g(0) is 1
3) Value of g(1) is -7
4) Value of g(-1) is -4/7
The given function is:
[tex]y=2(3.5)^x[/tex]
We know that when a function is reflected about the x-axis,
y becomes -y while x is unchanged.
So, the reflection of [tex]y=2(3.5)^x[/tex] about x-axis is:
[tex]-y=2(3.5)^x[/tex]
[tex]y=-2(3.5)^x[/tex]
[tex]g(x)=-2(3.5)^x[/tex]
g(x) is an exponential function defined everywhere.
[tex]g(0) =-2[/tex]
[tex]g(1) =-7[/tex]
[tex]g(-1) =-\frac{4}{7}[/tex]
Therefore, 1) The reflected function [tex]g(x)=-2(3.5)^x[/tex] is defined everywhere.
2) Initial value of g(x) or g(0) is 1
3) Value of g(1) is -7
4) Value of g(-1) is -4/7
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Answer:
The function f(x) = 2(3.5)x is reflected across the x-axis to create g(x).
What is the function definition of g(x)?
g(x) =
✔ –2
(3.5x)
What is the initial value of g(x)?
✔ –2
What are the outputs for inputs of –1 and 1 in g(x)?
g(−1) =
✔ –0.57
g(1) =
✔ –7
Step-by-step explanation:
Ed22
