Respuesta :
Answer:
Center is [tex](7,-4)[/tex]
Step-by-step explanation:
Recall that the equation for a circle is [tex](x-h)^2+(y-k)^2=r^2[/tex] with center [tex](h,k)[/tex] and radius [tex]r[/tex]. Hence, the center is [tex](h,k)\rightarrow(7,-4)[/tex].
just a quick addition to the great reply above by "goddessboi"
[tex]\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad radius=\stackrel{}{ r} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ (x-7)^2+(y+4)=9\implies [x-\stackrel{h}{7}]^2+[y-(\stackrel{k}{-4})]^2=3^2~\hfill \stackrel{vertex}{(7~~,~~-4)}[/tex]
