To find the equation for f , one must find the sum of the torque which will be :
Σ[tex]\left \ r[/tex]ⁿ = - F D + Fₙ d
When you express the force in terms of Fₙ, d , and D, the equation for (f) will be:
F = [tex]\frac{F{n} {d}}{D}[/tex]
The magnitude of the net force that is said to be acting on an object is generally said to be the same with the mass of the object and then it is multiplied by the acceleration of the object.
Note that the magnitude of the force is said to be the summation of all the forces that are said to be acting on an object.
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To crack a nut a force of magnitude (or greater) must be applied on both sides, as shown in the figure. One can see that a nutcracker only applies this force at the point in which it contacts the nut (at a distance from the nutcracker pivot). In this problem the nut is placed in a nutcracker and equal forces of magnitude are applied to each end, directed perpendicular to the handle, at a distance from the pivot. The frictional forces between the nut and the nutcracker are equal and large enough that the nut doesn't shoot out of the nutcracker
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