The volume of oil inside the tank at [tex]t = 15\,h[/tex] is approximately 66.556 liters.
How to estimate volume capacity by Riemann sum
In this question we must estimate the volume by Riemann sum, which consist in sum of all areas of the trapezoids of equal width in the volume rate versus time graph. The right Riemann sum with three intervals for this case is described below:
[tex]Q = \Sigma \limits_{i=0}^{2} \left\{R_{i}+\frac{1}{2}\cdot [R_{i+1}-R_{i}] \right\}\cdot \Delta t[/tex]
[tex]Q = \left[6.5+\frac{1}{2}\cdot (6.2-6.5) \right]\cdot (3.667)+\left[6.2+\frac{1}{2}\cdot (5.9-6.2)\right]\cdot (3.667) +\left[5.9+\frac{1}{2}\cdot (5.6-5.9) \right]\cdot (3.667)[/tex]
[tex]Q \approx 66.556\,L[/tex]
The volume of oil inside the tank at [tex]t = 15\,h[/tex] is approximately 66.556 liters. [tex]\blacksquare[/tex]
Remark
The table of the volume rate versus time is missing, all missing values of the table are included below:
[tex]R(4) = 6.5\,\frac{L}{h}[/tex], [tex]R(7.667) = 6.2\,\frac{L}{h}[/tex], [tex]R(11.333) = 5.9\,\frac{L}{h}[/tex], [tex]R(15) = 5.6\,\frac{L}{h}[/tex]
To learn more on Riemann sum, we kindly invite to check this verified question: https://brainly.com/question/21847158
