The 99% confidence interval for the population mean will be x± [tex]\frac{2.58 s}{\sqrt{n} }[/tex].
A confidence interval is a set of calculations for an unrecognized parameter that is specified as a range with a lower and upper bound.
If we take an n-sample from a normal population and wish to estimate the population mean, the confidence interval for the mean is:
[tex]\bar x[/tex]±[tex]Z_\frac{\alpha }{2} \times \frac{s}{\sqrt{n} }[/tex]
The level of significance is found by;
[tex]\rm \alpha =1- \ condifidence\ level \\\\\ \rm \alpha =1- 0.99 \\\\\ \rm \alpha = 0.001[/tex]
The value of z is
[tex]\rm Z_{\frac{\alpha}{2}} = \rm Z_{\frac{0.01}{2}} = Z_{0.005}=2.58[/tex]
Hence the 99% confidence interval for the population mean will be x± [tex]\frac{2.58 s}{\sqrt{n} }[/tex].
To learn more about the confidence interval refer to the link;
https://brainly.com/question/2396419
