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A simple random sample of 90 is drawn from a normally distributed population, and the mean is found to be 138, with a standard deviation of 34. what is the 90% confidence interval for the population mean? use the table below to help you answer the question. confidence level 90% 95% 99% z*-score 1.645 1.96 2.58 remember, the margin of error, me, can be determined using the formula m e = startfraction z times s over startroot n endroot endfraction. 128.75 to 147.25 130.98 to 145.02 132.10 to 143.90 137.38 to 138.62

Respuesta :

The 90% confidence interval for the population mean is (132.1, 143.9). Then the correct option is C.

What is the margin of error?

The probability or the chances of error while choosing or calculating a sample in a survey is called the margin of error.

A simple random sample of 90 is drawn from a normally distributed population, and the mean is found to be 138, with a standard deviation of 34.

The 90% confidence interval for the population mean. Then we have

[tex]\rm Margin \ of \ error = z * \dfrac{Standard \ deviation}{\sqrt{sample \ size}}\\\\\\\Margin \ of \ error = 1.645 * \dfrac{34}{\sqrt{90}}\\\\\\Margin \ of \ error = 5.9[/tex]

The interval will be given as

Mean ± Margin of error

138 ± 5.9

Then the interval will be (132.1, 143.9).

More about the margin of error link is given below.

https://brainly.com/question/6979326

Answer:

The answer is C. 132.10 to 143.90

Step-by-step explanation:

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