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a ball is rolled at a velocity of 12 miles per second. after 36 seconds, it comes to a stop. what is the acceleration of the ball?

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TheAestheticBoy

Question :-

  • A Ball is Rolled at a Velocity of 12 m/s. After 36 sec , it comes to a stop. What is the Acceleration of the ball ?

Answer :-

  • Acceleration is -0.33 m/s² .

Explanation :-

As per the provided information in the given question, we have been given that the Velocity of the ball is 12 m/s . Time is given as 36 sec . And, we have been asked to calculate the Acceleration .

For calculating the Acceleration , we will use the Formula :-

[tex] \bigstar \: \: \boxed{ \sf{ \: Acceleration \: = \: \dfrac{v \: - \: u}{t} \: }} [/tex]

Where ,

  • V denotes to the Final Velocity
  • U denotes to the Initial Velocity
  • T denotes to the Time Taken

Therefore , by Substituting the given values in the above Formula :-

[tex] \dag \: \: \: \sf { Acceleration \: = \: \dfrac{Final \: Velocity \: - \: Initial \: Velocity}{Time} } [/tex]

[tex] \longmapsto \: \: \sf { Acceleration \: = \: \dfrac{0 \: - \: 12}{36}} [/tex]

[tex]\longmapsto \: \: \sf {Acceleration \: = \: \dfrac{ \: 12 \: }{36}}[/tex]

[tex]\longmapsto \: \: \sf {Acceleration \: = \: \dfrac{ \: 1 \: }{3}}[/tex]

[tex] \longmapsto \: \bf {Acceleration \: = \: 0.33 \: m/s^{2}} [/tex]

Hence :-

  • Acceleration of Ball is -0.33 m/s² .

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