The magnitude, m, of an earthquake is defined to be m = log startfraction i over s endfraction, where i is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and s is the intensity of a "standard" earthquake, which is barely detectable. what is the magnitude of an earthquake that is 1,000 times more intense than a standard earthquake? use a calculator. round your answer to the nearest tenth. 2 3 4.5 6.9

Respuesta :

The magnitude, M, of an earthquake is 1.544 units when the magnitude of an earthquake is 1,000 times more intense than a standard earthquake

It is given that the magnitude of m, of an earthquake, is defined as:

[tex]\rm M=log\frac{I}{S}[/tex]

Where 'I' is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and 'S' is the intensity of a "standard" earthquake.

It is required to find the magnitude of the earthquake that is 1,000 times more intense than a standard earthquake.

What is Logarithm?

It is another way to represent the power of numbers and we say that 'b' is the logarithm of 'c' with base 'a' if and only if 'a' to the power 'b' equals 'c'.

[tex]\rm a^b=c\\\rm log_ac=b[/tex]

We have:

[tex]\rm M=log\frac{I}{S}[/tex]

and  [tex]\rm I=35S[/tex]  putting this value in the above equation, we get:

[tex]\rm M=log\frac{35S}{S}[/tex]

[tex]\rm M=log35[/tex]

[tex]\rm M=1.544[/tex]  (From log table)

Thus, The magnitude, M, of an earthquake is 1.544 units.

Learn more about the Logarithm here:

brainly.com/question/163125

Answer:

M=3

Step-by-step explanation: