The solution of the [tex]\rm log(2t+4)=log(14-3t)[/tex] is 2.
It is given that the [tex]\rm log(2t+4)=log(14-3t)[/tex].
It is required to find the value of 't'.
It is another way to represent the power of numbers and we say that 'b' is the logarithm of 'c' with base 'a' if and only if 'a' to the power 'b' equals 'c'.
[tex]\rm a^b=c\\\rm log_ac=b[/tex]
We have:
[tex]\rm log(2t+4)=log(14-3t)[/tex]
Taking [tex]\rm log_1_0[/tex] base and removing the log from both sides.
[tex]\rm 2t+4=14-3t\\\rm 5t=10\\\rm t=2[/tex]
Thus, the solution of the [tex]\rm log(2t+4)=log(14-3t)[/tex] is 2.
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