The height from which the engineer needs to release the ball is : 11.811 m
Given data:
Mass of wrecking ball = 52 kg
velocity of wrecking ball ( Vf ) = 12.3 m/s
Initial velocity of ball ( Vi ) = 0 m/s
final height ( hf ) = 4.1 m
Determine the height from which the engineer releases the ball
Applying the principle of energy conservation
Initial energy = final energy
= 1/2 mV²i + mghi = 1/2 mV²f + mghf ----- ( 1 )
given that Vi = 0 also cancelling out m from both sides
Equation ( 1 ) becomes
= 0 + hi = V²f / 2g + hf
therefore : hi = ( 12.3 )² / 2 * 9.81 + 4.1
= 151.29 / 19.62 + 4.1
= 11.811 m
Hence we can conclude that The height from which the engineer needs to release the ball is : 11.811 m
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