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If a point charge has a charge of + 3.2 x 10-19 C, what is the
magnitude of the electric force acting on the point charge
located in an electric field with an intensity of 5.0 x 103 N/C?
X

Respuesta :

facundo3141592

By using Coulomb's law, we conclude that the magnitude of the electromagnetic force is  1.6*10^(-15) N

What is the magnitude of the force?

For a charge q, located on an electric field E, the force is given by:

F = E*q

In this case, we know that:

  • E = 5.0*10^3 N/C
  • q = 3.2*10^(-19) C

Such that the direction will depend on the direction of the field and the sign of the charge, but we only care for the magnitude of the force.

Replacing that on the force equation, we get:

F = ( 5.0*10^3 N/C)*(3.2*10^(-19) C) = 1.6*10^(-15) N

If you want to learn more about the electromagnetic force, you can read:

https://brainly.com/question/13370981

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