Respuesta :

When the object falls through a viscous fluid with terminal velocity the total downward force becomes equal to total upward force

[tex]\\ \rm\rightarrowtail mg=U+F_v[/tex]

[tex]\\ \rm\rightarrowtail mg=m_1g+6\pi \eta rv_T[/tex]

[tex]\\ \rm\rightarrowtail (m-m_1)g=6\pi \eta rv_T[/tex]

[tex]\\ \rm\rightarrowtail v\rho g=6\pi \eta rv_T[/tex]

[tex]\\ \rm\rightarrowtail \dfrac{4}{3}\pi r^3(\rho-\sigma)g=6\pi\eta rv_T[/tex]

[tex]\\ \rm\rightarrowtail v_T=\dfrac{4gr^2(\rho-\sigma)}{18\eta}[/tex]

[tex]\\ \rm\rightarrowtail v_T=\dfrac{2}{9}\dfrac{gr^2(\rho-\sigma)}{\eta}[/tex]

  • [tex]\eta[/tex] is viscosity
  • r is radius of tube
  • v_T is terminal velocity
  • m is mass
  • [tex]\rho [/tex]is density of object
  • [tex]\sigma[/tex] is density of fluid
  • g is acceleration due to gravity