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142.8 g of NaCl is dissolved in enough water to make a 2.3 L of solution, what is the molarity of the solution?

A solution contains 67.5 % of magnesium chloride (MgCl2) dissolved in water. What is the molality of the solution?

62.5 g of sugar (C12H22O11) was dissolved in water to produce 250 g of sugar syrup. Calculate the molality and mole fraction of sugar in the syrup. For your answer please follow this: m = 0.5 and Xsugar = 0.5

What are the mole fractions of hydrochloric acid (HCl) and water in a 48% solution? For your answer format follow this: Xsolute = 0.5 and Xsolvent = 0.5

A 0.770 M solution of potassium nitrate (KNO3) contains 1.75 mol of solute. Calculate the volume of the solution.

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pstnonsonjoku

Stoichiometry can be used to determine the molality, molarity and volume of substances in a reaction.

What is concentration?

The term concentration refers to the amount of substance present in a solution.

1. Number of moles of NaCl = 142.8 g /52 gg/mol = 2.7 moles

Molarity =  2.7 moles/  2.3 L = 1.17 M

2. 67.5 % of magnesium chloride implies 67.5 g of MgCl2 in 100 g of solution.

Number of moles of MgCl2 = 67.5 g/95 g/mol = 0.7 moles

molality = 0.7 moles/32.5 * 10^-3 = 21.5 m

3. Number of moles of the sugar = 62.5 g/342 g/mol = 0.18 moles

Number of moles of water = 250 g/18 g/mol = 13.9 moles

Since 1 g of water = 1 cm^3 water

Molarity =  0.18 moles/250  * 10^-3 = 0.72M

Molality =  0.18 moles/250  * 10^-3 = 0.72m

Mole fraction of sugar = 0.18/(0.18 + 13.9 ) = 0.01

Mole fraction of water =  13.9 /(0.18 + 13.9 ) = 0.99

4. A 48% solution of HCl contains 48 g of HCl in 100 g of water.

Number of moles of HCl = 48 g/36.5 g/mol = 1.3 moles

Number of moles of water = 52g/18 g/mol = 2.9 moles

Mole fraction of HCl = 1.3/(1.3 + 2.9) = 0.31

Mole fraction of water = 2.9/(1.3 + 2.9) =0.69

5. 1.75 mol  =  0.770 M  * V

V =  1.75 mol/0.770 M

V = 2.27 L

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