Ratio remains same
[tex]\\ \sf\Rrightarrow \dfrac{x}{16}=\dfrac{9}{12}[/tex]
[tex]\\ \sf\Rrightarrow \dfrac{x}{16}=\dfrac{3}{4}[/tex]
[tex]\\ \sf\Rrightarrow 4x=48[/tex]
[tex]\\ \sf\Rrightarrow x=12[/tex]
#2
[tex]\\ \sf\Rrightarrow \dfrac{4}{10}=\dfrac{6}{x}[/tex]
[tex]\\ \sf\Rrightarrow \dfrac{2}{5}=\dfrac{6}{x}[/tex]
[tex]\\ \sf\Rrightarrow 2x=30[/tex]
[tex]\\ \sf\Rrightarrow x=15[/tex]
x=12
[tex]\frac{x}{16}=\frac{9}{12}[/tex]
[tex]x=12[/tex]
See the parsing
[tex](x+6)^2={10}^2+x^2[/tex]
[tex]x^2+12x+36=100+\lambda^2[/tex]
[tex]12x=64[/tex]
[tex]x=\frac{16}{3}[/tex]
{[tex]theorem[/tex]
I hope this helps you
:)
