Answer:
0.01 (nearest hundredth)
Step-by-step explanation:
[tex]\mathsf{probability=\dfrac{number \ of \ favorable \ outcomes}{number \ of \ total \ outcomes}}[/tex]
Total number of marbles (total outcomes) = 2 + 6 + 7 = 15
⇒ Probability of the first marble being red = [tex]\dfrac{2}{15}[/tex]
As there is no replacement, the total number marbles is now 15 and there is only 1 red marble left.
⇒ Probability of the second marble being red = [tex]\dfrac{1}{14}[/tex]
So the probability of the 1st and 2nd marble being red is:
[tex]\dfrac{2}{15}\times \dfrac{1}{14} = \dfrac{1}{105}[/tex] = 0.01 (nearest hundredth)
