|| ▼ Answer ▼ ||
The orbital period is 31.62 years when the average distance from the sun is 10AU
|| ✪ Explanation✪ ||
Given:
The average distance of the planet from the sun is r = 10 AU
To find the orbital period.
According to Kepler's third law,
[tex]T^{2}[/tex] ∞ [tex]r^{3}[/tex]
[tex]T^{2} =kr^{3}[/tex]
[tex]T=\frac{3}{2}[/tex]
Here, the constant k is taken to be 1.
Substituting the values, the orbital speed will be
[tex]T=(10)\frac{3}{2}[/tex]
[tex]=31.62~years[/tex]
Final Answer: The orbital period is 31.62 years when the average distance from the sun is 10AU
Hope this helps!
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