Answer:
[tex]-\frac{5y}{3}+\frac{5}{2}[/tex]
Step-by-step explanation:
Given Problem;
[tex]\frac{5}{6}\left(-2y+3\right)[/tex]
Solve;
[tex]\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac[/tex]
[tex]\frac{5}{6}\left(-2y+3\right)=\frac{5}{6}\left(-2y\right)+\frac{5}{6}\cdot \:3[/tex]
[tex]=\frac{5}{6}\left(-2y\right)+\frac{5}{6}\cdot \:3[/tex]
[tex]\mathrm{Simplify\;=\frac{5}{6}\left(-2y\right)+\frac{5}{6}\cdot \:3:}-\frac{5y}{3}+\frac{5}{2}[/tex]
[tex]=-\frac{5y}{3}+\frac{5}{2}[/tex]
Hence, Answer = [tex]-\frac{5y}{3}+\frac{5}{2}[/tex]
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