Respuesta :

tloh677

Answer:

5) y=2x^2+16x+32

Step-by-step explanation:

So the following equations on your paper are in vertex form. We want to turn these into standard form.

Remember, standard form is ax^2+bx+c and vertex form is y=a(x-h)^2+k

Lets expand our first problem, y=2(x+4)^2

y=2(x+4)(x+4)

y=2(x^2+8x+16)

y=2x^2+16x+32

Our answer for question 5 is y=2x^2+16x+32

If you need help with the other questions just add a comment.

HayabusaBrainly

Answer:

#5

  • y = 2(x + 4)^2
  • y = 2((x + 4)(x + 4))
  • y = 2(x(x + 4) + 4(x + 4))
  • y = 2(x^2 + 4x + 4x + 16)
  • y = 2(x^2 + 8x + 16)
  • y = 2x^2 + 16x + 32

#6

  • y = -2(x + 2)^2
  • y = -2((x + 2)(x + 2))
  • y = -2(x(x + 2) + 2(x + 2))
  • y = -2(x^2 + 2x + 2x + 4)
  • y = -2(x^2 + 4x + 4)
  • y = -2x^2 - 8x - 8

#7

  • y = -(x + 7)^2
  • y = -((x + 7)(x + 7))
  • y = -(x(x + 7) + 7(x + 7))
  • y = -(x^2 + 7x + 7x + 49)
  • y = -(x^2 + 14x + 49)
  • y = -x^2 - 14x - 49

#8

  • y = (x - 5)^2 + 9
  • y = (x - 5)(x - 5) + 9
  • y = x(x - 5) + (-5)(x - 5) + 9
  • y = x^2 - 5x - 5x + 25 + 9
  • y = x^2 - 10x + 25 + 9
  • y = x^2 - 10x + 36

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