The new molarity of the solution is 0.5M.
The molarity of a solution can be calculated by using the following expression:
C1V1 = C2V2
Where;
According to this question, a chemist dilutes 2.0 L of a 1.5 M solution with water until the final volume is 6.0 L.
1.5 × 2 = 6 × C2
3 = 6C2
C2 = 3/6 = 0.5M
Therefore, the new molarity of the solution is 0.5M.
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