Given :
[tex]\longrightarrow \sf \qquad {6x}^{2} + 10x - 56[/tex]
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We can write it as,
[tex]\longrightarrow \sf \qquad2 \bigg({3x}^{2} + 5x - 28 \bigg)[/tex]
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We have to find the two numbers a and b such that,
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[tex]\longrightarrow \sf \qquad a + b = 5[/tex]
[tex]\longrightarrow \sf \qquad a b = 84[/tex]
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Obviously, the two numbers are 7 and 12.
[tex]{\longrightarrow \sf \qquad2 \bigg({3x}^{2} - 7x + 12x- 28 \bigg)}[/tex]
[tex]{\longrightarrow \sf \qquad2 \bigg[x \bigg(3x-7 \bigg) +4 \bigg(3x-7\bigg)} \bigg][/tex]
[tex]{\longrightarrow \sf \qquad{2 \bigg(3x - 7 \bigg) \bigg(x + 4\bigg)}}[/tex]
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Therefore,
[tex]{\longrightarrow \bf \qquad{2 \bigg(3x - 7 \bigg) \bigg(x + 4\bigg)} \: is \: equivalent} \bf \: \: to \: \: {6x}^{2} + 10x - 56[/tex]
