Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. what is the solution set of this problem? (negative infinity, negative 21) (negative infinity, negative 21 right-bracket left-bracket negative 21, positive infinity) (21, positive infinity)

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vintechnology vintechnology · Answer 1 · 2022-03-31T12:13:56+02:00

The solution set of Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26 is x ≤ 21

Inequalities are expressions that have <, >, ≤ or ≥. Therefore,

let the number = x

Five times the sum of a number and 27 is as follows:

5(x + 27)

Six times the sum of that number and 26 is as follows:

6(x + 26)

Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26 is as follows:

5(x + 27) ≥ 6(x + 26)

Therefore,

5(x + 27) ≥ 6(x + 26)

5x + 135 ≥ 6x + 156

-x ≥ 21

x ≤ 21

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