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Twelve different video games showing substance use were observed and the duration of times of game play​ (in seconds) are listed below. The design of the study justifies the assumption that the sample can be treated as a simple random sample. Use the sample data to construct a 98% confidence interval estimate of ​o, the standard deviation of the duration times of game play. Assume that this sample was obtained from a population with a normal distribution.

4058, 4336, 4707, 3927, 4718, 4139
4789, 4982, 4096, 4066, 4567, 3801

The confidence interval estimate is ___

Respuesta :

Using the t-distribution, as we have the standard deviation for the population, it is found that the confidence interval estimate is (4044.2, 4653.4).

What is a t-distribution confidence interval?

The confidence interval is:

[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]

In which:

  • [tex]\overline{x}[/tex] is the sample mean.
  • t is the critical value.
  • n is the sample size.
  • s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed 98% confidence interval, with 12 - 1 = 11 df, is t = 2.7181.

As for the other parameters, they are given by:

[tex]\overline{x} = 4348.8, s = 388.2, n = 12[/tex]

Hence:

[tex]\overline{x} - t\frac{s}{\sqrt{n}} = 4348.8 - 2.7181\frac{388.2}{\sqrt{12}} = 4044.2[/tex]

[tex]\overline{x} + t\frac{s}{\sqrt{n}} = 4348.8 + 2.7181\frac{388.2}{\sqrt{12}} = 4653.4[/tex]

The confidence interval estimate is (4044.2, 4653.4).

To learn more about the t-distribution, you can check https://brainly.com/question/16162795

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