If 45.0 grams of magnesium hydroxide is heated, the amount of water that will be produced would be 13.90 grams
From the equation of the reaction:
Mg(OH)₂ → MgO + H₂O
The mole ratio of Mg(OH)₂ to H₂O is 1:1
Mole of 45 grams Mg(OH)₂ = 45/58.33 = 0.77 moles
Thus, the equivalent mole of H₂O produced would also be 0.77 moles.
Mass of 0.77 moles H₂O = 0.77 x 18.02 = 13.90 grams
More on stoichiometric calculations can be found here: https://brainly.com/question/8062886
