Assuming a 4.00 litre of a sample gas at 1.00 atm compressed to 0.800 litre at constant temperature. Calculate the final presure of the gas.

Respuesta :

At constant temperature, the final pressure of the compressed gas is 5.0atm.

Given the data in the question;

  • Initial volume of the gas; [tex]V_1 = 4L[/tex]
  • Initial Pressure; [tex]P_1 = 1.0atm[/tex]
  • Final volume; [tex]V_2 = 0.800L[/tex]

Final pressure; [tex]P_2 = \ ?[/tex]

Boyle's law

Boyle's law states that the volume V of a given quantity of gas is inversely proportional to its pressure P at constant temperature.

It is expressed as;

[tex]P_1V_1 = P_2V_2[/tex]

Where [tex]P_1[/tex] is Initial Pressure, [tex]V_1[/tex] Initial volume, [tex]P_2[/tex] is Final Pressure and [tex]V_2[/tex] is Final volume.

To determine the final pressure of the gas, we substitute our given values into the expression above.

[tex]P_1V_1 = P_2V_2\\\\P_2 = \frac{P_1V_1}{V_2} \\\\P_2 = \frac{1.0atm \ *\ 4L}{0.800L}\\ \\P_2 = \frac{1.0atm \ *\ 4}{0.800}\\\\P_2 = \frac{4.0atm}{0.800}\\\\P_2 = 5.0atm[/tex]

Therefore, at constant temperature, the final pressure of the compressed gas is 5.0atm

Learn more about Boyle's law: brainly.com/question/1437490