Please assist, no links

Answer:
[tex]\frac{1}{a^{7} }[/tex]
Step-by-step explanation:
Use this rule:
[tex]\frac{x^a}{x^b}=x^{a-b}[/tex]
So, this gives you
[tex]a^{-13+6}[/tex]
This equates to:
[tex]a^{-7}[/tex]
However, we cant leave the exponent negative, so we use this formula:
[tex]a^{-b}=\frac{1}{a^b}[/tex]
So, the answer is:
[tex]\frac{1}{a^{7} }[/tex]
Answer:
There is no denominator a^-7
The power is positive 1/a^7
Step-by-step explanation:
Remark
We are not told what the restrictions on the power are. Here are the possibilities.
So I will give the answer to both conditions. You will have to choose.
There is no denominator
That means that The powers are subtracted
Multiply numerator and denominator by a+6
a^- 13 * a^6
=========
a^-6 * a^6
To start a^(-6 + 6) = a^0 which = 1. That is not written, so you are left with a^ (-13 + 6) = a ^ -7
The answer must have a positive power.
Multiply the numerator and denominator by a^13.
numerator
a^-13 * a^13
a^(-13 + 13)
a^0
1
So we are left with 1 in the numerator.
a^-6 * a^13
a^(-6 + 13)
a^7
Answer: what is left is 1/a^7