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A quantity of gas has a volume of 250 L, at 290 K and 303.98 kPa of pressure. What volume must the gas be for the gas to be at 273 K and at 101.33 kPa?

Respuesta :

Eduard22sly

The new volume of the gas at a temperature of 273 K and at pressure of 101.33 KPa is 706.01 L

Data obtained from the question

  • Initial volume (V₁) = 250 L
  • Initial temperature (T₁) = 290 K
  • Initial pressure (P₁) = 303.98 KPa
  • New temperature (T₂) = 273 K
  • New pressure (P₂) = 101.33 KPa
  • New Volume (V₂) =?

How to determine the new volume

The new volume of the gas can be obtained by using the combined gas equation as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

(303.98 × 250) / 290 = (101.33 × V₂) / 273

Cross multiply

290 × 101.33 × V₂ = 303.98 × 250 × 273

Divide both side by 290 × 101.33

V₂ = (303.98 × 250 × 273) / (290 × 101.33)

V₂ = 706.01 L

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