Answer:
[tex]y=0x+2[/tex]
Step-by-step explanation:
Given the following question:
Point A = (3, 2) = (x1, y1)
Point B = (-6, 2) = (x2, y2)
To write the following points in slope intercept form we first need to calculate the slope by using the formula for slope or rise over run.
[tex]m=\frac{y2-y1}{x2-x1}[/tex]
[tex]m=\frac{2-2}{-6-3} =\frac{0}{-9}[/tex]
[tex]0\div-9=0[/tex]
[tex]m=0[/tex]
Now that we have to slope, we can now write the points in slope intercept form by using the formula y = mx + b and solve for b.
[tex]y=mx+b[/tex]
[tex]y=2[/tex]
[tex]m=0[/tex]
[tex]x=3[/tex]
[tex]2=0(3)+b[/tex]
[tex]0\times3=0[/tex]
[tex]2=0+b[/tex]
[tex]2+0=2[/tex]
[tex]2=b[/tex]
[tex]b=2[/tex]
[tex]y=0x+2[/tex]
Your answer in slope intercept form is "y = 0x + 2."
Hope this helps.
