Does anyone know the answer? Pls help

Answer:
x = 24
Step-by-step explanation:
First, substitute x = -6y into the top equation:
-6y + 3y = 12
-3y = 12
Divide both sides by -3, and you get:
y = -4
Now, you plug in the y value to the second equation:
x = -6(-4)
x =24
Given :
[tex]{ \longrightarrow\qquad \sf x + 3y = 12 \: –––– \sf \: (i)}[/tex]
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[tex]{ \longrightarrow\qquad \sf x = - 6y \: –––– \sf \: (ii)}[/tex]
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(i) – (ii) we get :
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[tex]{ \longrightarrow \qquad \sf \: {x + 3y -x = 12 - ( - 6y)}}[/tex]
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[tex]{ \longrightarrow \qquad \sf \: { \cancel{x} + 3y \: \cancel{ - \: x }= 12 + 6y}}[/tex]
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[tex]{ \longrightarrow \qquad \sf \: { 3y - 6y = 12 }}[/tex]
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[tex]{ \longrightarrow \qquad \sf \: { - \: 3y = 12 }}[/tex]
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[tex]{ \longrightarrow \qquad \sf {- \: y = \dfrac{12}{3} }}[/tex]
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[tex]{ \longrightarrow \qquad \bf \: { y = - \: 4 }}[/tex]
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Now, Substituing the value of y in equation (i) :
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[tex] \longrightarrow \qquad \sf{x + 3( - 4)= 12}[/tex]
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[tex] \longrightarrow \qquad \sf{x - 12= 12}[/tex]
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[tex] \longrightarrow \qquad \sf{x = 12 + 12}[/tex]
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[tex]\longrightarrow \qquad \bf{x = 24}[/tex]
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Therefore,