Answer:
[tex](-3, 5)[/tex]
Step-by-step explanation:
Isolate x from the first equation:
[tex]x=\frac{11-4y}{3}[/tex]
Now, substitute it in the second equation:
[tex]\begin{bmatrix}2\cdot \frac{11-4y}{3}+y=-1\end{bmatrix}[/tex]
This gives you:
[tex]\begin{bmatrix}\frac{22-5y}{3}=-1\end{bmatrix}[/tex]
So, you conclude: y = 5
Next, we substitute y = 5 into [tex]x=\frac{11-4y}{3}[/tex]
So, we get:
[tex]x=\frac{11-4\cdot \:5}{3}[/tex]
Then:
[tex]x=-3[/tex]
Finally, we have to put it into the coordinate form:
[tex](-3, 5)[/tex]
