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How far from the door must a ramp begin in order to rise 5 ft with an 11-degree angle of elevation? Round off your answer to the nearest hundredth.


PS. Please put a drawing/illustration. Thank you!

Respuesta :

The door of the ramp must begin at a distance of 25.72ft in order to raise the ramp by 5ft.

Data;

  • height (opposite) = 5ft
  • angle = 11°
  • distance (adjacent) =x

Trigonometric Ratio

To solve this problem, this is a right angle triangle and we can use trigonometric ratio SOHCAHTOA here.

Since we have the value of angle and opposite and solving only for adjacent, we can use tangent of the angle.

[tex]tan \theta = \frac{opposite}{adjacent} \\[/tex]

Let's substitute the values into the formula above and solve

[tex]tan 11 = \frac{5}{x} \\x = \frac{5}{tan 11} \\x = 25.72ft[/tex]

The door of the ramp must begin at a distance of 25.72ft in order to raise the ramp by 5ft.

Learn more on trigonometric ratio here;

https://brainly.com/question/11967894

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