How tall would a building have to be if, after hitting the ground ten times, the ball bounces to 1 m? Is there a building this tall?

Respuesta :

The building should be 1.024 meters high and unfortunately there are no buildings with such height in the world.

How to estimate the height of a building by geometric progressions

In this question we must use definition of geometric progression to predict initial height ([tex]h_{o}[/tex]), in meters, in terms of current height ([tex]h[/tex]), in meters, and number of bounces experimented by the ball ([tex]n[/tex]). The expression is described below:

[tex]h = h_{o}\cdot \left(\frac{1}{2} \right)^{n}[/tex]   (1)

If we know that [tex]n = 10[/tex] and [tex]h = 1\,m[/tex], then the initial height is:

[tex]1 = h_{o}\cdot \left(\frac{1}{2} \right)^{10}[/tex]

[tex]h_{o} = 2^{10}[/tex]

[tex]h_{o} = 1024\,m[/tex]

The building should be 1.024 meters high and unfortunately there are no buildings with such height in the world. [tex]\blacksquare[/tex]

Remark

The statement is incomplete, complete form is shown below:

A ball falls from the roof of a building and bounces half as high each time. How tall would a building have to be if, after hitting the ground ten times, the ball bounces to 1 meter? Is there a building this tall?

To learn more on geometric series, we kindly invite to check this verified question: https://brainly.com/question/15130111