Answer:
[tex]4 < \sqrt{17} < 5[/tex]
Step-by-step explanation:
Mumble. The square root is something called "monotonic", which means that [tex]a > b \Leftrightarrow \sqrt a > \sqrt b[/tex]
A neat trick to solve this will be: go back from 17 till you find a perfect square, then add 1 to it:
In our case it's easy to do it, since the number before 17 is a perfect square already ([tex]16=4^2[/tex]), so we can pick it as the lower bound, and then add 1 to the base to find the next one ([tex]4+1= 5)[/tex]
