Respuesta :
The number of grams of iron present in 14.79 cm length of the same iron rod is 640.51 g.
What is ounces?
Ounces is a unit of mass which is used to define a very little amount of anything.
In the question, given that:
In one inch of iron rod whose weighs is 3.88 ounces = 2.54 cm long
In 1 g = 0.035273 ounces present
So we can calcuylate the number of grams in which 3.88 ounces present as:
x = (3.88 ounces) / (0.035273 ounces/g)
x = 110g
So, in 110g = 3.88 ounces present
And in 2.54 cm = 110g of iron present
In 14.79 cm, present grams of iron can be calculated as:
y = (14.79cm x 110g) / 2.54cm
y = 640.51 g
Hence option (c) is correct i.e. 640.51 g.
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https://brainly.com/question/24505595
The weight of the iron rod with 14.79 cm length with same density is given by: Option C; 640.51 g
How are density, volume and mass of a substance related?
Suppose that a finite amount of substance is there having its properties as:
- mass of substance = m kg
- density of substance = d kg/m³
- volume of that substance = v m³
Then, they are related as:
[tex]d = \dfrac{m}{v}[/tex]
We know that:
- 1 ounce = 28.3495 g approx
Now, from the facts given in the problem, we have:
The weight of first iron rod which is one inches long = 3.88 ounces
The new rod is 14.79 cm long. And 1 cm = 0.3937 inches approx, thus the new rod is: [tex]14.79 \times 0.3937 \approx 5.8228 \: \rm inches[/tex]
As for 1 inch long rod, there is weight of 3.88 ounces, thus:
for 5.8228 inch rod, the weight of the rod would be [tex]5.8228 \times 3.88 \approx 22.5924 \: \rm ounces[/tex]
And since 1 ounce = 28.3495 g approx
Thus, weight of the new rod in grams would be [tex]22.5924\times 28.3495 \approx 640.485 \approx 640.51\: \rm g[/tex]
Thus, the weight of the iron rod with 14.79 cm length with same density is given by: Option C; 640.51 g
Learn more about density here:
https://brainly.com/question/952755
