The value of the equilibrium constant for the reverse reaction is 5 × 10⁻⁶.
The equilibrium constant is the value of the reaction quotient at equilibrium.
Given that at a certain temperature, the value of the equilibrium constant, K, for the reaction represented above is 2.0 × 10⁵.
We require the equilibrium constant for the reverse reaction at the same temperature.
Let K' be the equilibrium constant for the reverse reaction.
So, we have that K' = 1/K
Substituting the value of K into the equation, we have
K' = 1/K
K' = 1/(2.0 × 10⁵)
K' = 1/2.0 × 1/10⁵
K' = 0.5 × 10⁻⁵
K' = 5 × 10⁻⁶.
So, the value of the equilibrium constant for the reverse reaction is 5 × 10⁻⁶.
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