|| ▼ Answer ▼ ||
The average rate of change per year from 1 to 5 is 8inches
Step-by-step explanation:
Given
[tex]h=t^{2}+2t+10[/tex]
The average rate of change = [tex]\frac{h(5)-h(1)}{5-1}[/tex]
Now h(5)
[tex]\boxed{h(5)=-5^{2}+2(5)+10 }[/tex]
[tex]\boxed{h(5)=25+10+10}[/tex]
[tex]\boxed{h(5)=45}[/tex]
Now, h(1)
[tex]\boxed{h(1)=-1^{2}+2(1)+10}[/tex]
[tex]\boxed{h(1)=1+2+10}[/tex]
[tex]\boxed{h(1)=13}[/tex]
[tex]\boxed{Average~change~rate=\frac{h(5)-h(1)}{5-1} }[/tex]
[tex]\boxed{Average~change~rate=\frac{45-13}{5-1}=\frac{32}{4}=8 }[/tex]
The final answer
The average rate of change per year from 1 to 5 is 8 inches
Hope this helps!
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