Respuesta :
The two values when the provided quadratic equation is solved for the x are -4.41 and -1.59 to the nearest hundredth.
What is a quadratic equation?
A quadratic equation is the equation in which the unknown variable is one and the highest power of the unknown variable is two.
The standard form of the quadratic equation is,
[tex]ax^2+bx+c=0[/tex]
Here, (a,b,c) are the real numbers and x is the variable.
To find the value of x, the following formula is used,
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
The given equation is,
[tex]2(x+ 3)^2 - 4 = 0[/tex]
To solve this equation, we need to apply some mathematical operations over it. Let's start with opening the brackets.
[tex]2(x+ 3)^2 - 4 = 0\\2(x^2+6x+9)-4=0\\2x^2+12x+14-4\\2x^2+12x+12=0\\x^2+6x+7=0[/tex]
On comparing with standard equation we get,
[tex]a=1, b=6, c=7[/tex]
Put this values in the above formula,
[tex]x=\dfrac{-(6)\pm\sqrt{(6)^2-4(1)(7)}}{2(1)}\\x=\dfrac{-(6)\pm\sqrt{(6)^2-4(1)(7)}}{2(1)}\\x=-4.41,-1.59[/tex]
Hence, the two values when the provided quadratic equation is solved for the x are -4.41 and -1.59 to the nearest hundredth.
Learn more about the quadratic equation here;
https://brainly.com/question/1214333
