The area of the sector of the circle will be 759.34 m². It is the amount of area enclosed inside the sector's perimeter.
The area of a circle's sector is the amount of space encompassed inside the sector's perimeter. The origin of a sector is always the circle's center.
The region of a circle encompassed by its two radii and the arc connecting them is known as the sector of a circle.
The given data in the problem is;
[tex]\rm \theta[/tex] is the central angle=[tex]\frac{10\pi}{7}[/tex]= 4.485
r is the radius = 18.4 m
The area of a sector of a circle is found as;
[tex]\rm A= \frac{\theta}{2} \pi r^2 \\\\ \rm A= \frac{4.485}{2} \times (18.4)^2 \\\\ \rm A=759.34 \ m^2[/tex]
Hence the area of the sector of the circle will be 759.34 m².
To learn more about the area of the sector refer to the link;
https://brainly.com/question/1582027
