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220 mL of oxygen gas was collected over water. The total pressure of oxygen plus water vapor was 745.8 mmHg at 25.0°C. What is the pressure, in mmHg, exerted by only the oxygen gas?

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Since 220 mL of oxygen gas was collected over water, the pressure exerted by only the oxygen gas is 720.8 mmHg

Pressure of gas collected over water

The total pressure of a gas collected over water is given by P = P' + p where

  • P = pressure of oxygen gas and
  • p = vapour pressure of water at 25 °C = 25 mmHg

Making P' subject of the formula, we have

P' = P - p

Since the total pressure of oxygen plus water vapor is P = 745.8 mmHg, substituting the values of the variables into the equation, we have

P' = P - p

P' = 745.8 mmHg - 25 mmHg

P' = 720.8 mmHg

So, Since 220 mL of oxygen gas was collected over water, the pressure exerted by only the oxygen gas is 720.8 mmHg

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